Integrand size = 13, antiderivative size = 43 \[ \int \sin (a+b x) \sin (c+d x) \, dx=\frac {\sin (a-c+(b-d) x)}{2 (b-d)}-\frac {\sin (a+c+(b+d) x)}{2 (b+d)} \]
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Time = 0.05 (sec) , antiderivative size = 43, normalized size of antiderivative = 1.00, number of steps used = 4, number of rules used = 2, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.154, Rules used = {4665, 2717} \[ \int \sin (a+b x) \sin (c+d x) \, dx=\frac {\sin (a+x (b-d)-c)}{2 (b-d)}-\frac {\sin (a+x (b+d)+c)}{2 (b+d)} \]
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Rule 2717
Rule 4665
Rubi steps \begin{align*} \text {integral}& = \int \left (\frac {1}{2} \cos (a-c+(b-d) x)-\frac {1}{2} \cos (a+c+(b+d) x)\right ) \, dx \\ & = \frac {1}{2} \int \cos (a-c+(b-d) x) \, dx-\frac {1}{2} \int \cos (a+c+(b+d) x) \, dx \\ & = \frac {\sin (a-c+(b-d) x)}{2 (b-d)}-\frac {\sin (a+c+(b+d) x)}{2 (b+d)} \\ \end{align*}
Time = 0.23 (sec) , antiderivative size = 43, normalized size of antiderivative = 1.00 \[ \int \sin (a+b x) \sin (c+d x) \, dx=\frac {\sin (a-c+(b-d) x)}{2 (b-d)}-\frac {\sin (a+c+(b+d) x)}{2 (b+d)} \]
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Time = 0.34 (sec) , antiderivative size = 40, normalized size of antiderivative = 0.93
method | result | size |
default | \(\frac {\sin \left (a -c +\left (b -d \right ) x \right )}{2 b -2 d}-\frac {\sin \left (a +c +\left (b +d \right ) x \right )}{2 \left (b +d \right )}\) | \(40\) |
risch | \(\frac {\sin \left (x b -d x +a -c \right )}{2 b -2 d}-\frac {\sin \left (x b +d x +a +c \right )}{2 \left (b +d \right )}\) | \(41\) |
parallelrisch | \(\frac {\left (b +d \right ) \sin \left (a -c +\left (b -d \right ) x \right )-\sin \left (a +c +\left (b +d \right ) x \right ) \left (b -d \right )}{2 b^{2}-2 d^{2}}\) | \(49\) |
norman | \(\frac {-\frac {2 b \tan \left (\frac {d x}{2}+\frac {c}{2}\right )}{b^{2}-d^{2}}+\frac {2 d \tan \left (\frac {a}{2}+\frac {x b}{2}\right )}{b^{2}-d^{2}}+\frac {2 b \tan \left (\frac {a}{2}+\frac {x b}{2}\right )^{2} \tan \left (\frac {d x}{2}+\frac {c}{2}\right )}{b^{2}-d^{2}}-\frac {2 d \tan \left (\frac {a}{2}+\frac {x b}{2}\right ) \tan \left (\frac {d x}{2}+\frac {c}{2}\right )^{2}}{b^{2}-d^{2}}}{\left (1+\tan \left (\frac {a}{2}+\frac {x b}{2}\right )^{2}\right ) \left (1+\tan \left (\frac {d x}{2}+\frac {c}{2}\right )^{2}\right )}\) | \(147\) |
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Time = 0.25 (sec) , antiderivative size = 42, normalized size of antiderivative = 0.98 \[ \int \sin (a+b x) \sin (c+d x) \, dx=\frac {d \cos \left (d x + c\right ) \sin \left (b x + a\right ) - b \cos \left (b x + a\right ) \sin \left (d x + c\right )}{b^{2} - d^{2}} \]
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Leaf count of result is larger than twice the leaf count of optimal. 153 vs. \(2 (32) = 64\).
Time = 0.31 (sec) , antiderivative size = 153, normalized size of antiderivative = 3.56 \[ \int \sin (a+b x) \sin (c+d x) \, dx=\begin {cases} x \sin {\left (a \right )} \sin {\left (c \right )} & \text {for}\: b = 0 \wedge d = 0 \\\frac {x \sin {\left (a - d x \right )} \sin {\left (c + d x \right )}}{2} - \frac {x \cos {\left (a - d x \right )} \cos {\left (c + d x \right )}}{2} - \frac {\sin {\left (a - d x \right )} \cos {\left (c + d x \right )}}{2 d} & \text {for}\: b = - d \\\frac {x \sin {\left (a + d x \right )} \sin {\left (c + d x \right )}}{2} + \frac {x \cos {\left (a + d x \right )} \cos {\left (c + d x \right )}}{2} - \frac {\sin {\left (a + d x \right )} \cos {\left (c + d x \right )}}{2 d} & \text {for}\: b = d \\- \frac {b \sin {\left (c + d x \right )} \cos {\left (a + b x \right )}}{b^{2} - d^{2}} + \frac {d \sin {\left (a + b x \right )} \cos {\left (c + d x \right )}}{b^{2} - d^{2}} & \text {otherwise} \end {cases} \]
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Time = 0.25 (sec) , antiderivative size = 40, normalized size of antiderivative = 0.93 \[ \int \sin (a+b x) \sin (c+d x) \, dx=-\frac {\sin \left (b x + d x + a + c\right )}{2 \, {\left (b + d\right )}} - \frac {\sin \left (-b x + d x - a + c\right )}{2 \, {\left (b - d\right )}} \]
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Time = 0.29 (sec) , antiderivative size = 40, normalized size of antiderivative = 0.93 \[ \int \sin (a+b x) \sin (c+d x) \, dx=-\frac {\sin \left (b x + d x + a + c\right )}{2 \, {\left (b + d\right )}} + \frac {\sin \left (b x - d x + a - c\right )}{2 \, {\left (b - d\right )}} \]
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Time = 20.71 (sec) , antiderivative size = 84, normalized size of antiderivative = 1.95 \[ \int \sin (a+b x) \sin (c+d x) \, dx=\frac {d\,\left (\frac {\sin \left (a+c+b\,x+d\,x\right )}{2}+\frac {\sin \left (a-c+b\,x-d\,x\right )}{2}\right )}{b^2-d^2}-\frac {b\,\left (\frac {\sin \left (a+c+b\,x+d\,x\right )}{2}-\frac {\sin \left (a-c+b\,x-d\,x\right )}{2}\right )}{b^2-d^2} \]
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